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hdu 2066 一个人的旅行 (dij+heap)

2013-03-11 10:43 309 查看
Problem - 2066

  入门SP,用dij+heap 0ms通过。

View Code

#define REP(i, n) for (int i = 0; i < (n); i++)
#define REP_1(i, n) for (int i = 1; i <= (n); i++)
typedef pair<LL, int> PLI;
#define PB push_back
#define MPR make_pair
#define FI first
#define SE second

VPII rel
;
LL dis
;
multiset<PLI> HP;

void input(int n, int s, int t) {
REP(i, 1002) rel[i].clear(), dis[i] = linf;
HP.clear();
int a, b, d;
REP(i, n) {
scanf("%d%d%d", &a, &b, &d);
rel[a].PB(MPR(b, d));
rel[b].PB(MPR(a, d));
}
REP(i, s) {
scanf("%d", &a);
rel[0].PB(MPR(a, 0));
}
REP(i, t) {
scanf("%d", &a);
rel[a].PB(MPR(1001, 0));
}
//    puts("OK!");
}

LL dijHeap(int s, int t) {
dis[s] = 0ll;
HP.insert(MPR(0ll, s));
while (true) {
int id = HP.begin()->SE;
//        cout << "size " << SZ(HP) << endl;
//        cout << id << ' ' << HP.begin()->FI << ' ' << dis[id] << endl;
if (id == t) return HP.begin()->FI;
HP.erase(HP.begin());
REP(i, SZ(rel[id])) {
int x = rel[id][i].FI, d = rel[id][i].SE;
if (dis[x] > dis[id] + d) {
//                cout << x << ' ' << dis[x] << endl;
if (dis[x] != linf) HP.erase(MPR(dis[x], x));
HP.insert(MPR(dis[x] = dis[id] + d, x));
}
}
}
}

int main() {
//    freopen("in", "r", stdin);
int n, s, t;
while (~scanf("%d%d%d", &n, &s, &t)) {
input(n, s, t);
cout << dijHeap(0, 1001) << endl;
}
return 0;
}


——written by Lyon
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