UVA 455 - Periodic Strings
2013-03-03 03:08
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A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc"
has period 3, since it is formed by 4 repetitions of the string "abc". It also has periods 6 (two repetitions of "abcabc") and 12 (one repetition of "abcabcabcabc").
Write a program to read a character string and determine its smallest period.
of up to 80 non-blank characters. Two consecutive input will separated by a blank line.
#define RUN
#ifdef RUN
#include <stdio.h>
#include <string.h>
int main() {
#ifndef ONLINE_JUDGE
freopen("455.in", "r", stdin);
freopen("455.out", "w", stdout);
#endif
int n;
char word[100];
scanf("%d", &n);
getchar();
for(int k=0; k<n; k++){
getchar();
memset(word, 0, sizeof(word));
scanf("%s", word);
int len = strlen(word);
for (int i = 1; i <= len; i++){
if (len % i == 0) { // 符合条件的必能被i整除
int ok = 1;
for (int j = i; j < len; j++){
if (word[j] != word[j % i]){
ok = 0;
break;
}
}
if (ok) {
printf("%d\n", i);
break;
}
}
}
if(k != n-1){
printf("\n");
}
}
return 0;
}
#endif
has period 3, since it is formed by 4 repetitions of the string "abc". It also has periods 6 (two repetitions of "abcabc") and 12 (one repetition of "abcabcabcabc").
Write a program to read a character string and determine its smallest period.
Input
The first line oif the input file will contain a single integer N indicating how many test case that your program will test followed by a blank line. Each test case will contain a single character stringof up to 80 non-blank characters. Two consecutive input will separated by a blank line.
Output
An integer denoting the smallest period of the input string for each input. Two consecutive output are separated by a blank line.Sample Input
1 HoHoHo
Sample Output
2
#define RUN
#ifdef RUN
#include <stdio.h>
#include <string.h>
int main() {
#ifndef ONLINE_JUDGE
freopen("455.in", "r", stdin);
freopen("455.out", "w", stdout);
#endif
int n;
char word[100];
scanf("%d", &n);
getchar();
for(int k=0; k<n; k++){
getchar();
memset(word, 0, sizeof(word));
scanf("%s", word);
int len = strlen(word);
for (int i = 1; i <= len; i++){
if (len % i == 0) { // 符合条件的必能被i整除
int ok = 1;
for (int j = i; j < len; j++){
if (word[j] != word[j % i]){
ok = 0;
break;
}
}
if (ok) {
printf("%d\n", i);
break;
}
}
}
if(k != n-1){
printf("\n");
}
}
return 0;
}
#endif
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