您的位置:首页 > 其它

LeetCode25:Remove Duplicates from Sorted Array

2013-02-23 06:18 369 查看
Given a sorted array, remove the duplicates in place such that each element appear only once and return
the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,

Given input array A =
[1,1,2]
,

Your function should return length =
2
,
and A is now
[1,2]
.

public class Solution {
public int removeDuplicates(int[] A) {
// Start typing your Java solution below
// DO NOT write main() function
if(A.length<1)
return 0;
int curValue=A[0];
int curIndex=1;
for(int i=1; i<A.length; i++){
if(curValue!=A[i]){
curValue=A[i];
if(curIndex!=i)
A[curIndex]=A[i];
curIndex++;
}
}
return curIndex;
}
}


------------------------------------------------------------------------------------------------------------------------------------------

LL's solution:

public class Solution {
public int removeDuplicates(int[] A) {
// Start typing your Java solution below
// DO NOT write main() function
int len = A.length;
if(len<2)
return len;
int start = 0, window = 1;
int current = A[start];
while(start+window<len){
if(current<A[start+window]){
start++;
current = A[start];
if(window!=1){   // repeating
window--;
A[start] = A[start+window];
current = A[start];
}
}
else{
window++;
}
}
return start+1;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: