[结题报告]10082 - WERTYU Time limit: 3.000 seconds

Problem C: WERTYU

A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.

Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control,etc.] are not represented in the input. You are to replace each letter or punction symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.

Sample Input

O S, GOMR YPFSU/

Output for Sample Input

I AM FINE TODAY.

参考代码:
把字符换成键盘的左边一个字符(最左边的,回车的控制键无效),不多说,上代码..

#include<stdio.h>
int main()
{
char a;
while(scanf("%c",&a)!=EOF)
{if(a=='=') printf("-");
else if(a=='-')printf("0");
else if(a=='0')printf("9");
else if(a=='9')printf("8");
else if(a=='8')printf("7");
else if(a=='7')printf("6");
else if(a=='6')printf("5");
else if(a=='5')printf("4");
else if(a=='4')printf("3");
else if(a=='3')printf("2");
else if(a=='2')printf("1");
else if(a=='1')printf("`");
else if(a=='\\')printf("]");
else if(a==']')printf("[");
else if(a=='[')printf("P");
else if(a=='P')printf("O");
else if(a=='O')printf("I");
else if(a=='I')printf("U");
else if(a=='U')printf("Y");
else if(a=='Y')printf("T");
else if(a=='T')printf("R");
else if(a=='R')printf("E");
else if(a=='E')printf("W");
else if(a=='W')printf("Q");
else if(a=='\'')printf(";");
else if(a==';')printf("L");
else if(a=='L')printf("K");
else if(a=='K')printf("J");
else if(a=='J')printf("H");
else if(a=='H')printf("G");
else if(a=='G')printf("F");
else if(a=='F')printf("D");
else if(a=='D')printf("S");
else if(a=='S')printf("A");
else if(a=='/')printf(".");
else if(a=='.')printf(",");
else if(a==',')printf("M");
else if(a=='M')printf("N");
else if(a=='N')printf("B");
else if(a=='B')printf("V");
else if(a=='V')printf("C");
else if(a=='C')printf("X");
else if(a=='X')printf("Z");
else printf("%c",a);
}
return 0;
}