杭电ACM HDU 1019 Least Common Multiple
2013-02-15 23:58
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Least Common Multiple
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 20576 Accepted Submission(s): 7674
Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where
m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
Sample Input
2 3 5 7 15 6 4 10296 936 1287 792 1
Sample Output
105 10296
Source
East Central North America 2003, Practice
Recommend
JGShining
#include <cstdio> int gcd(int a,int b){return b?gcd(b,a%b):a;} int lcm(int a,int b){return a/gcd(a,b)*b;} int main(){ int t,n,a,b; scanf("%d",&t); while(t--){ scanf("%d",&n); scanf("%d",&a); for(int i=1;i<n;i++){ scanf("%d",&b); a=lcm(a,b); } printf("%d\n",a); } }
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