获取系统时间

1. 获取当前时间字符串

#include <time.h>

time_t t = time(NULL);

struct tm *tm = localtime(&t);

printf("%4d-%02d-%02d %02d:%02d:%02d\n",

tm->tm_year + 1900, tm->tm_mon + 1,

tm->tm_mday, tm->tm_hour,

tm->tm_min, tm->tm_sec);

2. 字符串转 时间

#include <iostream>

#include <fstream>

#include <time.h>

using namespace std;

int main(int argc, char *argv[]) {

time_t tt = time(NULL);

cout << (long)tt <<endl;

const char*date="2012-02-14 14:00:00"; //这个时间格式 必须与strptime中相同

tm t;

if (strptime(date,"%Y-%m-%d %H:%M:%S",&t)) {

time_t ttt=mktime(&t);

cout <<(long)ttt <<endl;

printf("%d/%d/%d %d:%d:%d\n",t.tm_year+1900,

t.tm_mon+1,t.tm_mday,t.tm_hour, t.tm_min, t.tm_sec);

} else

cout << "strptime error.";

}