HDU-1846:Brave Game
2013-01-15 22:19
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/*话说是最水的博弈题- -,刚刚学习 Bash Game,即 n = (m+1)*r + s 其中s<=m 即如果s = 0,(n%(m+1)==0)那么是先手败。 否则先手胜 */ #include<iostream> using namespace std; int main() { int n,m,t; cin>>t; while(t--) { cin>>n>>m; if (n%(m+1)!=0) cout<<"first"<<endl; else cout<<"second"<<endl; } return 0; }
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