Oracle 生成uuid

1、在Oracle SQL 提供了一个生成uuid的函数sys_guid:

SQL> select sys_guid() from dual ;

SYS_GUID()

CBD38B8F81A4447AAE2D343D1AE09972

2、为了使产生的uuid符合rfc 4122的标准

创建函数如下，测试通过。

CREATE OR REPLACE

FUNCTION getuuid

RETURN VARCHAR

IS

guid VARCHAR (50);

BEGIN

guid := lower(RAWTOHEX(sys_guid()));

RETURN

substr(guid,1,8)||'-'||substr(guid,9,4)||'-'||substr(guid,13,4)||'-'||substr(guid,17,4)||'-'||substr(guid,21,12);

END getuuid;

SQL> select getuuid from dual ;

GET_UUID

--------------------------------------------------------------------------------

5ce0830e-d399-49f8-a68b-c761fca05140