python比数字游戏

今天看到了一个题目，需要输入一个数字，表示成绩和他的成绩的级别：

A: 90--100

B: 80--89

C: 70--79

D: 60--69

E: < 60

需求在上面大家都看到了，加入输入90-100之间，表示你的级别在A;输入80--89之间，表示你的级别是B;输入的是70--79之间，表示你的级别是C;输入60--69之间，表示你的级别是D;输入小于60，表示你没有通过；

除了上面的判断之外，我们还需要判断输入的是字符还是数字类型，本来还需要考虑整数和负数的问题，但是由于负数有（负号）-，输入-21之后，系统判断是字符，不是数字类型了，所以这里就不考虑负数了。

脚本很简单，下面我吧脚本贴上来，感兴趣的童鞋可以看看：

[root@centos6 20130113]# cat aa.py
#!/usr/bin/env python
print "This script make you input your number \n"
print "Then will show your level..."
def compare(number):
if number > 100:
print "Your input is too high"
elif number >=90 and number <= 100:
print "Your Level is A"
elif number >=80 and number < 90:
print "Your Level is B"
elif number >=70 and number < 80:
print "Your Level is C"
elif number >=60 and number < 70:
print "Your Level is D"
elif number < 60:
print "You not pass"

def main():
while True:
number=raw_input("Please input your number:")
if number.isdigit():
Input=int(number)
print "Your input is ",Input
compare(Input)
print "Press Ctrl + C to exit..."
else:
print "Please input character ..."
print "Press Ctrl + C to exit..."

main()

下面来看看运行的效果吧：

[root@centos6 20130113]# ./aa.py
This script make you input your number

Then will show your level...
Please input your number:100
Your input is  100
Your Level is A
Press Ctrl + C to exit...
Please input your number:99
Your input is  99
Your Level is A
Press Ctrl + C to exit...
Please input your number:88
Your input is  88
Your Level is B
Press Ctrl + C to exit...
Please input your number:77
Your input is  77
Your Level is C
Press Ctrl + C to exit...
Please input your number:66
Your input is  66
Your Level is D
Press Ctrl + C to exit...
Please input your number:55
Your input is  55
You not pass
Press Ctrl + C to exit...
Please input your number:-100
Please input character ...
Press Ctrl + C to exit...
Please input your number:ijdf
Please input character ...
Press Ctrl + C to exit...
Please input your number: