UVA 465 Overflow
2012-12-22 23:51
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练习C++bign类高精度,这一题数据中含有前导0,必须在重载=号时处理一下,而且必须以char类型的数组输入,一开始我用bign类输入,会报错的,我WA了至少30多次。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <string> #include <algorithm> #include <climits> using namespace std; const int MAXN = 40000; const int INF = 2147483647; char str1[MAXN], str2[MAXN]; struct bign { int len, s[MAXN]; bign () { memset(s, 0, sizeof(s)); len = 1; } bign (int num) {*this = num;} bign (const char *num) { *this = num ;} bign operator = (const char* num) { for(int i = 0; num[i] == '0'; num++) ; //去前导0,很重要。 len = strlen(num); for(int i = 0; i < len; i++) { s[i] = num[len-i-1] - '0'; } return *this; } bign operator = (int num) { char s[MAXN]; sprintf(s, "%d", num); *this = s; return *this; } bign operator + (const bign& b) const { bign c; c.len = 0; for(int i = 0, g = 0; g || i < max(len, b.len); i++) { int x = g; if(i < len) x += s[i]; if(i < b.len) x += b.s[i]; c.s[c.len++] = x % 10; g = x / 10; } return c; } void clean() { while(len > 1 && !s[len-1]) len--; } bign operator * (const bign &b) const { bign c; c.len = len + b.len; for(int i = 0; i < len; i++) { for(int j = 0; j < b.len; j++) { c.s[i+j] += s[i] * b.s[j]; } } for(int i = 0; i < c.len; i++) { c.s[i+1] += c.s[i] / 10; c.s[i] %= 10; } c.clean(); return c; } bign operator += (const bign &b) { *this = *this + b; return *this; } bool operator < (const bign &b) { if(len != b.len) return len < b.len; for(int i = len-1; i >= 0; i--) { if(s[i] != b.s[i]) return s[i] < b.s[i]; } return false; } bool operator > (const bign &b) { if(len != b.len) return len > b.len; for(int i = len-1; i >= 0; i--) { if(s[i] != b.s[i]) return s[i] > b.s[i]; } return false; } bool operator == (const bign &b) { return !(*this > b) && !(*this < b); } string str() const { string res = ""; for(int i = 0; i < len; i++) res = char(s[i]+'0') + res; if(s[len-1] == 0) res = ""; if(res == "") res = "0"; return res; } }; istream& operator >> (istream &in, bign &x) { string s; in >> s; x = s.c_str(); return in; } ostream& operator << (ostream &out, bign &x) { out << x.str(); return out; } int main() { char ope; bign a, b; while(~scanf("%s", str1)) { scanf(" %c", &ope); scanf("%s", str2); printf("%s %c %s\n", str1, ope, str2); a = str1, b = str2; if(a > INF) printf("first number too big\n"); if(b > INF) printf("second number too big\n"); if(ope == '+' && a+b > INF) printf("result too big\n"); else if(ope == '*' && a*b > INF) printf("result too big\n"); } return 0; }
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