您的位置:首页 > 其它

UVA 709 Formatting Text

2012-12-19 11:10 232 查看
  d[i][j]表示第i个词于第j列开始,且后面的词按规则摆放的最小代价。因为怕搞错多解时的答案,所以用了逆推。

//709 	Formatting Text 	Accepted 	C++ 	0.020 	2012-12-19 03:06:24
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
const int MAXN = 80+5, MAXM = 10000+5;
const int INF = 0x3f3f3f3f;
int N, len[MAXM], d[MAXM][MAXN], p[MAXM][MAXN];
char word[MAXM][MAXN], line[MAXM];
int main()
{
while (scanf("%d", &N) && N)
{
gets(line);
int n = 0;
while (gets(line))
{
if (!line[0])
break;
for (int p = 0; line[p]; )
{
sscanf(line+p, "%s", word[++n]);
len
= strlen(word
);
p += len
;
while (line[p] == ' ')
p++;
}
}
len[n+1] = INF;
fill(d[n+1]+1, d[n+1]+1+N, INF);
d[n+1][1] = 0;
for (int i = n; i >= 1; i--)
{
fill(d[i]+1, d[i]+1+N, INF);
if (d[i+1][1]+(len[i] < N ? 500 : 0) < d[i][1])
{
d[i][1] = d[i+1][1]+(len[i] < N ? 500 : 0);
p[i][1] = 1;
}
if (d[i+1][1] < d[i][N-len[i]+1])
{
d[i][N-len[i]+1] = d[i+1][1];
p[i][N-len[i]+1] = 1;
}
for (int j = 1; j-1+len[i] <= N; j++)
for (int k = j+len[i]+1; k-1+len[i+1] <= N; k++)
if (d[i+1][k]+(k-j-len[i]-1)*(k-j-len[i]-1) < d[i][j])
{
d[i][j] = d[i+1][k]+(k-j-len[i]-1)*(k-j-len[i]-1);
p[i][j] = k;
}
}
for (int i = 1, j = 1; i <= n; i++)
{
printf("%s", word[i]);
if (p[i][j] > 1)
{
int x = sqrt(d[i][j]-d[i+1][p[i][j]]);
for (int k = 0; k <= x; k++)
printf(" ");
}
else
printf("\n");
j = p[i][j];
}
printf("\n");
}
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: