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C++中取出的字节数组转为结构

2012-12-11 11:09 465 查看
byte[] BytePara = 为从C++里取出的字节数组;

InfoDataStruct 为结构,循环将Byte数组里的内容转换为结构

InfoDataStruct* p = (InfoDataStruct*)(BytePara+ (i * 55));

InfoDataStruct dataStruct= BytesToStruct<InfoDataStruct>(BytePara, (i * 55));

///不使用泛型,会使得编码繁琐。

public static object BytesToStruct(byte[] bytes, int startIndex, Type strcutType)
{
int size = Marshal.SizeOf(strcutType);
IntPtr buffer = Marshal.AllocHGlobal(size);
try
{
Marshal.Copy(bytes, startIndex, buffer, size);
return Marshal.PtrToStructure(buffer, strcutType);
}
finally
{
Marshal.FreeHGlobal(buffer);
}
}

/// <summary>
/// byte数组转为结构
/// </summary>
/// <typeparam name="T">结构</typeparam>
/// <param name="bytes">数组</param>
/// <param name="startIndex">起始位置</param>
/// <returns></returns>
public static T BytesToStruct<T>(byte[] bytes, int startIndex)
{
T Obj = default(T);
Type strcutType = typeof(T);
int size = Marshal.SizeOf(strcutType);
IntPtr buffer = Marshal.AllocHGlobal(size);
try
{
Marshal.Copy(bytes, startIndex, buffer, size);
Obj= (T) Marshal.PtrToStructure(buffer, strcutType);
return Obj;
}
finally
{
Marshal.FreeHGlobal(buffer);
}
}
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