UVa 579 - ClockHands
2012-11-14 04:54
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题目:计算时钟时针和分针的夹角。
分析:简单题。
注意:做差时夹角的范围(-360,360)
分析:简单题。
注意:做差时夹角的范围(-360,360)
#include <stdio.h> #include <stdlib.h> int main() { int H,M; while ( scanf("%d:%d",&H,&M) && H+M ) { double m = M*6.0; double h = H*30.0+M*0.5; double a = h-m; if ( a < 0 ) a += 360.0; if ( a > 180 ) a = 360.0-a; printf("%.3lf\n",a); } return 0; }
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