杭电ACM题 1036 Edge解题报告
2012-11-09 22:44
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Edge
Description
For products that are wrapped in small packings it is necessary that the sheet of paper containing the directions for use is folded until its size becomes small enough. We assume that a sheet of paper is rectangular and only folded
along lines parallel to its initially shorter edge. The act of folding along such a line, however, can be performed in two directions: either the surface on the top of the sheet is brought together, or the surface on its bottom. In both cases the two parts
of the rectangle that are separated by the folding line are laid together neatly and we ignore any differences in thickness of the resulting folded sheet.
After several such folding steps have been performed we may unfold the sheet again and take a look at its longer edge holding the sheet so that it appears as a one-dimensional curve, actually a concatenation of line segments. If we move along this curve in
a fixed direction we can classify every place where the sheet was folded as either type A meaning a clockwise turn or type V meaning a counter-clockwise turn. Given such a sequence of classifications, produce a drawing of the longer edge of the sheet assuming
90 degree turns at equidistant places.
Input
The input contains several test cases, each on a separate line. Each line contains a nonempty string of characters A and V describing the longer edge of the sheet. You may assume that the length of the string is less than 200.
The input file terminates immediately after the last test case.
Output
For each test case generate a PostScript drawing of the edge with commands placed on separate lines. Start every drawing at the coordinates (300,420) with the command "300 420 moveto". The first turn occurs at (310,420) using the
command "310 420 lineto". Continue with clockwise or counter-clockwise turns according to the input string, using a sequence of "x y lineto" commands with the appropriate coordinates. The turning points are separated at a distance of 10 units. Do not forget
the end point of the edge and finish each test case by the commands stroke and showpage.
You may display such drawings with the gv PostScript interpreter, optionally after a conversion using the ps2ps utility.
Sample Input
Sample Output
Source
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这题不难,就是题目看的比较蛋疼,其实就是当输入A时右转,V的时候左转,每次转后需要走10单位。
我设置了一个方向direc变量,用于记录当前的位置,用x和y记录坐标。我提交两次,一次RE,修改了string数组的大小,本来是20,改成200后就行了。
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AC代码:
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 1157 | Accepted: 811 |
For products that are wrapped in small packings it is necessary that the sheet of paper containing the directions for use is folded until its size becomes small enough. We assume that a sheet of paper is rectangular and only folded
along lines parallel to its initially shorter edge. The act of folding along such a line, however, can be performed in two directions: either the surface on the top of the sheet is brought together, or the surface on its bottom. In both cases the two parts
of the rectangle that are separated by the folding line are laid together neatly and we ignore any differences in thickness of the resulting folded sheet.
After several such folding steps have been performed we may unfold the sheet again and take a look at its longer edge holding the sheet so that it appears as a one-dimensional curve, actually a concatenation of line segments. If we move along this curve in
a fixed direction we can classify every place where the sheet was folded as either type A meaning a clockwise turn or type V meaning a counter-clockwise turn. Given such a sequence of classifications, produce a drawing of the longer edge of the sheet assuming
90 degree turns at equidistant places.
Input
The input contains several test cases, each on a separate line. Each line contains a nonempty string of characters A and V describing the longer edge of the sheet. You may assume that the length of the string is less than 200.
The input file terminates immediately after the last test case.
Output
For each test case generate a PostScript drawing of the edge with commands placed on separate lines. Start every drawing at the coordinates (300,420) with the command "300 420 moveto". The first turn occurs at (310,420) using the
command "310 420 lineto". Continue with clockwise or counter-clockwise turns according to the input string, using a sequence of "x y lineto" commands with the appropriate coordinates. The turning points are separated at a distance of 10 units. Do not forget
the end point of the edge and finish each test case by the commands stroke and showpage.
You may display such drawings with the gv PostScript interpreter, optionally after a conversion using the ps2ps utility.
Sample Input
V AVV
Sample Output
300 420 moveto 310 420 lineto 310 430 lineto stroke showpage 300 420 moveto 310 420 lineto 310 410 lineto 320 410 lineto 320 420 lineto stroke showpage
Source
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这题不难,就是题目看的比较蛋疼,其实就是当输入A时右转,V的时候左转,每次转后需要走10单位。
我设置了一个方向direc变量,用于记录当前的位置,用x和y记录坐标。我提交两次,一次RE,修改了string数组的大小,本来是20,改成200后就行了。
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AC代码:
/*********************** * 程序名:Edge.cpp * 功能:ACM ************************/ #include <iostream> #include <Cstring> using namespace std; #define start_x 300 #define start_y 420 #define move 10 int main() { char c, string[200]; int length, i, x, y; char direc; while(cin>>string) { direc = 'r'; x = start_x + move; y = start_y; length = strlen(string); cout<<start_x<<" "<<start_y<<" "<<"moveto"<<endl; cout<<start_x+move<<" "<<start_y<<" "<<"lineto"<<endl; for(i = 0; i < length; i++) { if(string[i] == 'V') { if(direc == 'r') { direc = 'u'; y += move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else if(direc == 'l'){ direc = 'd'; y -= move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else if(direc == 'u') { direc = 'l'; x -= move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else { direc = 'r'; x += move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } } else if(string[i] == 'A') { if(direc == 'r') { direc = 'd'; y -= move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else if(direc == 'l') { direc = 'u'; y += move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else if(direc == 'u') { direc = 'r'; x += move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } else { direc = 'l'; x -= move; cout<<x<<" "<<y<<" "<<"lineto"<<endl; } } } cout<<"stroke"<<endl<<"showpage"<<endl; } return 0; }
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