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Android自定义action与permission!!!

2012-11-06 09:28 381 查看
大家好,今天给大家简单分享一下Android中自定义action与permission. 我们在实际开发中,经常会用到系统的功能,比如打电话功能只要如以下简单代码:

[java]
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Uri uri = Uri.parse("tel.xxxxxx");

Intent it =new Intent(Intent.ACTION_CALL,uri);

startActivity(it);

[java]
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<uses-permission id="android .permission.CALL_PHONE" />

<uses-permission id="android .permission.CALL_PHONE" />


下面我将实例给大家分享一下自定义action与permission.实例有两个Android工程Demo,与Demo2. Demo工程有两个Activity一个是主Activity,另一个是ViewActivity,这个Activity我们给自定义了android.tutor.action.VIEW的action以及com.tutor.permission.VIEW的permission。

另一个Demo2的主Activity去调用Demo里的ViewActivity,代码如下:

[java]
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Intent mIntent = new Intent();

mIntent.setAction("android.tutor.action.VIEW");

startActivity(mIntent);

[java]
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<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>

<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>


下面是具体步骤如下:

第一步:新建第一个Android工程Demo.目录结构如下:



第二步:新建名为ViewActivity的Activity,代码如下:

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package com.tutor.demo;

import android.app.Activity;

import android.os.Bundle;

import android.widget.TextView;

public class ViewActivity
extends Activity {
@Override
protected
void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

TextView mTextView = new TextView(this);

mTextView.setText("我是自定义action并且加了权限的Activity.");

setContentView(mTextView);
}
}

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<?xml version="1.0" encoding="utf-8"?>

<manifest xmlns:android="http://schemas.android.com/apk/res/android"

package="com.tutor.demo"

android:versionCode="1"

android:versionName="1.0">

<permission android:protectionLevel="normal" android:name="com.tutor.permission.VIEW">

   </permission>

<application android:icon="@drawable/icon" android:label="@string/app_name">

<activity android:name=".Demo"

android:label="@string/app_name">

<intent-filter>
<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />

</intent-filter>
</activity>

<activity android:name=".ViewActivity"

android:label="自定义action与permission"

android:permission="com.tutor.permission.VIEW"

>
<intent-filter>
<action android:name="android.tutor.action.VIEW" />

<category android:name="android.intent.category.DEFAULT" />

</intent-filter>
</activity>
</application>
<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>

</manifest>

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.tutor.demo"
android:versionCode="1"
android:versionName="1.0">
<permission android:protectionLevel="normal" android:name="com.tutor.permission.VIEW">
     </permission>

<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".Demo"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>

<activity android:name=".ViewActivity"
android:label="自定义action与permission"
android:permission="com.tutor.permission.VIEW"
>
<intent-filter>
<action android:name="android.tutor.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</activity>
</application>
<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>
</manifest>


第四步:修改主Activity,Demo.java代码如下(在onCreate()里去跳转到ViewActivity,也需要申请权限的如上面的第28行代码):

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package com.tutor.demo;

import com.tutor.demo.R;

import android.app.Activity;

import android.content.Intent;

import android.os.Bundle;

public class Demo
extends Activity {

@Override
public void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

setContentView(R.layout.main);
//跳转ViewActivity
Intent mIntent = new Intent();

mIntent.setAction("android.tutor.action.VIEW");

startActivity(mIntent);
}
}

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package com.tutor.demo2;

import com.tutor.demo2.R;

import android.app.Activity;

import android.content.Intent;

import android.os.Bundle;

public class Demo2
extends Activity {
@Override

public void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

setContentView(R.layout.main);
//访问应用demo里的ViewActivity

Intent mIntent = new Intent();

mIntent.setAction("android.tutor.action.VIEW");

startActivity(mIntent);
}
}

package com.tutor.demo2;
import com.tutor.demo2.R;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
public class Demo2 extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
//访问应用demo里的ViewActivity
Intent mIntent = new Intent();
mIntent.setAction("android.tutor.action.VIEW");
startActivity(mIntent);
}
}


在Demo2工程里的AndroidMainifest.xml中申请权限,不加权限程序会报错,代码如下:

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<?xml version="1.0" encoding="utf-8"?>

<manifest xmlns:android="http://schemas.android.com/apk/res/android"

package="com.tutor.demo2"

android:versionCode="1"

android:versionName="1.0">

<application android:icon="@drawable/icon" android:label="@string/app_name">

<activity android:name=".Demo2"

android:label="@string/app_name">

<intent-filter>
<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />

</intent-filter>
</activity>
</application>
<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>

</manifest>

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.tutor.demo2"
android:versionCode="1"
android:versionName="1.0">
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".Demo2"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
<uses-permission android:name="com.tutor.permission.VIEW"></uses-permission>
</manifest>

运行之效果如下图所示:



一样的效果,呵呵,ok,今天就先讲到这里。
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