[SGU]113. Nearly prime numbers
2012-10-28 20:42
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Analysis
这题比112还要水……只用从2到sqrt(k)枚举整除的次数就行了。
Accepted Code
这题比112还要水……只用从2到sqrt(k)枚举整除的次数就行了。
Accepted Code
var n,i,j,k,t,p:longint; begin read(n); for i:=1 to n do begin read(k); t:=k; p:=0; for j:=2 to trunc(sqrt(k)+0.5) do while t mod j=0 do begin t:=t div j; inc(p); end; if t>1 then inc(p); if p=2 then writeln('Yes') else writeln('No'); end; end.
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