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hdu 4411 Arrest

2012-10-23 15:51 381 查看
解题报告说是上下界费用流,我这里用的也是上下界的方法,不用上下界也是一样的,把必经过的边的费用变成-inf,那么在求最小费用流时程序一定会经过这条边,同样起到了限制下界的作用,这样更好理解~

#pragma comment(linker, "/STACK:102400000,102400000")
#include<iostream>
#include<vector>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
#include<cmath>
#include<cassert>
#include<cstring>
#include<iomanip>
using namespace std;
#ifdef _WIN32
#define i64 __int64
#define out64 "%I64d\n"
#define in64 "%I64d"
#else
#define i64 long long
#define out64 "%lld\n"
#define in64 "%lld"
#endif
/************ for topcoder by zz1215 *******************/
#define FOR(i,a,b)      for( int i = (a) ; i <= (b) ; i ++)
#define FF(i,a)        for( int i = 0 ; i < (a) ; i ++)
#define FFD(i,a,b)      for( int i = (a) ; i >= (b) ; i --)
#define S64(a)          scanf(in64,&a)
#define SS(a)           scanf("%d",&a)
#define LL(a)           ((a)<<1)
#define RR(a)           (((a)<<1)+1)
#define pb              push_back
#define pf              push_front
#define X               first
#define Y               second
#define CL(Q)           while(!Q.empty())Q.pop()
#define MM(name,what)   memset(name,what,sizeof(name))
#define MC(a,b)         memcpy(a,b,sizeof(b))
#define MAX(a,b)        ((a)>(b)?(a):(b))
#define MIN(a,b)        ((a)<(b)?(a):(b))
#define read            freopen("in.txt","r",stdin)
#define write           freopen("out.txt","w",stdout)

const int inf = 0x3f3f3f3f;
const i64 inf64 = 0x3f3f3f3f3f3f3f3fLL;
const double oo = 10e9;
const double eps = 10e-9;
const double pi = acos(-1.0);
const int maxn = 222;
const int add = 111;
const int head = 220;
const int end = 221;

struct zz
{
	int from;
	int to;
	int c;
	int cost;
	int id;
}zx;

vector<zz>g[maxn];
int n,m,k;
int d[maxn][maxn];
int way[maxn];
bool inq[maxn];
int back[maxn];

void floyd()
{
	for(int k=0;k<=n;k++)
	{
		for(int i=0;i<=n;i++)
		{
			if(d[i][k]==inf) continue;
			for(int j=0;j<=n;j++)
			{
				if(d[k][j]==inf) continue;
 				d[i][j]=min(d[i][j],d[i][k]+d[k][j]);
			}
		}
	}
	return ;
}

void link(int now,int to,int c,int cost,int bc=0)
{
	zx.from=now;zx.to=to;zx.c=c;zx.cost=cost;zx.id=g[zx.to].size();
	g[zx.from].pb(zx);
	swap(zx.from,zx.to);zx.c=bc;zx.cost=-cost;zx.id=g[zx.to].size()-1;
	g[zx.from].pb(zx);
	return ;
}

bool spfa()
{
	for(int i=0;i<maxn;i++) way[i]=inf;
	MM(back,-1);
	queue<int>q;
	MM(inq,false);
	inq[head]=true;
	q.push(head);
	way[head]=0;
	int now,to,temp;
	while(!q.empty())
	{
		now = q.front();
		q.pop();
		for(int i=0;i<g[now].size();i++)
		{
			to = g[now][i].to;
			if(g[now][i].c>0)
			{
				temp = way[now]+g[now][i].cost;
				if(temp < way[to])
				{
					way[to]=temp;
					back[to]=g[now][i].id;
					if(!inq[to])
					{
						inq[to]=true;
						q.push(to);
					}
				}
			}
		}
		inq[now]=false;
	}
	return way[end]!=inf;
}

int dfs(int flow=inf,int to = end)
{
	if(to == head) return flow;
	int now = g[to][back[to]].to;
	int id = g[to][back[to]].id;
	int temp = dfs(min(g[now][id].c,flow),now);
	g[now][id].c-=temp;
	g[to][back[to]].c+=temp;
	return temp;
}

int ek()
{
	int ans=0;
	for(int i=0;i<n;i++)
	{
		ans+=d[i][i+1];
	}
	ans+=d[0]
;
	while(spfa())
	{
		ans+=dfs()*way[end];
	}
	return ans;
}

int main()
{
	while(cin>>n>>m>>k)
	{
		if(!m && !n && !k) return 0;
		for(int i=0;i<maxn;i++)
		{
			g[i].clear();
		}
		for(int i=0;i<=n;i++)
		{
			for(int j=0;j<=n;j++)
			{
				d[i][j]=inf;
			}
		}
		for(int i=0;i<=n;i++)
		{
			d[i][i]=0;
		}
		int now,to,len;
		for(int i=1;i<=m;i++)
		{
			cin>>now>>to>>len;
			d[now][to]=d[to][now]=min(d[now][to],len);
		}
		floyd();
		link(0,1,0,d[0][1],1);
		for(int i=2;i<=n;i++)
		{
			link(0,i,1,d[0][i]);
		}
		for(int i=1;i<n;i++)
		{
			link(i+add,end,1,d[i][0]);
		}
		link(n+add,end,0,d
[0],1);
		link(0,end,inf,0);
		link(head,0,k-1,0,1);
		for(int i=1;i<=n;i++)
		{
			link(i+add,i+1,0,d[i][i+1],1);
			for(int j=i+2;j<=n;j++)
			{
				link(i+add,j,1,d[i][j]);
			}
		}
		cout<<ek()<<endl;
	}
	return 0;
}
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