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hdu 1165 Eddy's research II (DP)

2012-10-14 17:39 447 查看
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当m=1时:

A(1,n) = A(0,A(1,n-1)) = A(1,n-1)+1

= A(0,A(1,n-2))+1 = A(1,n-2)+2.....

= A(1,n-n)+n = A(0,1)+n=n+2;

当m=2时:

A(2,n) = A(1,A(2,n-1)) = A(2,n-1)+2

= A(1,A(2,n-2))+2=A(2,n-2)+2*2...

= A(2,n-n)+2*n = 2*n+3;

当m=3时:

A(3,n) = A(2,A(3,n-1)) = 2*(A(3,n-1))+3;

 
#include"stdio.h"
__int64 A(__int64 m,__int64 n)
{
if(n==0) return A(m-1,1);
else if(m==1) return n+2;
else if(m==2) return 2*n+3;
else return 2*(A(3,n-1))+3;
}
int main()
{
__int64 n,m;
while(scanf("%I64d%I64d",&m,&n)!=EOF)
printf("%I64d\n",A(m,n));
return 0;
}
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