a letter and a number

a letter and a number

时间限制：3000 ms | 内存限制：65535 KB

难度：1
描述 we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;

Give you a letter x and a number y , you should output the result of y+f(x).
输入On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).输出for each case, you should the result of y+f(x) on a line样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

查看代码---运行号：252173----结果：Accepted

运行时间：2012-10-05 11:36:47 | 运行人:huangyibiao

view sourceprint?

01.

#include <iostream>

02.

using

namespace

std;

03.

04.

int

main()

05.

{

06.

int

testNum;

07.

cin >> testNum;

08.

char

letterX;

09.

int

numY;

10.

while

(testNum--)

11.

{

12.

cin >> letterX >> numY;

13.

if

(letterX -

'a'

>= 0)

//小写

14.

{

15.

cout << numY - (letterX -

'a'

) - 1 << endl;//别忘了-1

16.

}

17.

else

18.

cout << numY + (letterX -

'A'

) + 1 << endl;//别忘了加1

19.

}

20.

return

0;

21.

}