您的位置:首页 > Web前端 > JavaScript

JS获取URL参数方法

2012-09-12 17:27 639 查看
//js get url param
var getParam = function(name){
var search = document.location.search;
var pattern = new RegExp("[?&]"+name+"\=([^&]+)", "g");
var matcher = pattern.exec(search);
var items = null;
if(null != matcher){
try{
items = decodeURIComponent(decodeURIComponent(matcher[1]));
}catch(e){
try{
items = decodeURIComponent(matcher[1]);
}catch(e){
items = matcher[1];
}
}
}
return items;
};
getParam('PId');
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  url search null function