HDU 1002 大数运算 java 的强大功能
2012-09-05 09:16
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A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 123322 Accepted Submission(s): 23706
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using
32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line
between two test cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
java的强大运算,还记得当年学c++大数加法的时候整整看了一天这道题的代码,要转化成数组进行处理,一年后的今天,学会了大数加法处理这道题。
post code
import java.util.*;
import java.math.*;
import java.io.*;
public class Main //注意类名一定要用首字母大写的Main
{
public static void main( String[] args )
{
Scanner cin=new Scanner(new BufferedInputStream (System.in) );
BigInteger a,b,c; //定义了三个大整数
int ji,num=0;
ji=cin.nextInt(); //读入判断条件
while( ji>=1 )
{
ji--;
num++;
a=cin.nextBigInteger(); //读入大整数
b=cin.nextBigInteger();
c=a.add(b);
System.out.println("Case "+num+":"); //输出结果
System.out.println(a + " + " + b + " = "+c);
if(ji!=0)System.out.println("");
}
}
}
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