HDU 3498 whosyourdaddy【Dancing Links重复覆盖】
2012-09-04 09:59
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有n个单位的敌人,对某个敌人进行攻击时该敌人以及与其直接相邻的敌人都会被消灭。问消灭所有敌人所需的最少攻击次数。
重复覆盖问题。我把此题贴出来是想说剪枝优化很有必要,一个小细节就能决定是TLE还是AC。
重复覆盖问题。我把此题贴出来是想说剪枝优化很有必要,一个小细节就能决定是TLE还是AC。
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; const int maxn = 60*60 + 10; const int oo = 1 << 30; const int maxrow = 60; const int maxcol = 60; int mtx[maxrow][maxcol]; int n, m, ans; int totRow, totCol, head, idx; int L[maxn], R[maxn], U[maxn], D[maxn]; int RH[maxn], CH[maxn], S[maxn]; void initMtx() { memset(mtx, 0, sizeof(mtx)); for (int i = 0; i < n; ++i) { mtx[i][i] = 1; } int a, b; for (int i = 0; i < m; ++i) { scanf("%d%d", &a, &b); a--; b--; mtx[a][b] = mtx[b][a] = 1; } } int newNode(int up, int down, int left, int right) { U[idx] = up; D[idx] = down; L[idx] = left; R[idx] = right; U[down] = D[up] = L[right] = R[left] = idx; return idx++; } void build() { idx = maxn - 1; head = newNode(idx, idx, idx, idx); idx = 0; for (int j = 0; j < totCol; ++j) { newNode(idx, idx, L[head], head); CH[j] = j; S[j] = 0; } for (int i = 0; i < totRow; ++i) { int k = -1; for (int j = 0; j < totCol; ++j) { if (!mtx[i][j]) continue; if (-1 == k) { k = newNode(U[CH[j]], CH[j], idx, idx); RH[k] = i; CH[k] = j; S[j]++; } else { k = newNode(U[CH[j]], CH[j], k, R[k]); RH[k] = i; CH[k] = j; S[j]++; } } } } void remove(int c) { for (int i = D[c]; i != c; i = D[i]) { L[R[i]] = L[i]; R[L[i]] = R[i]; /*S[CH[i]]--;*/ } } void resume(int c) { for (int i = U[c]; i != c; i = U[i]) { L[R[i]] = R[L[i]] = i; /*S[CH[i]]++;*/ } } /*估价函数*/ int h() { bool vis[maxcol]; memset(vis, false, sizeof(vis)); int ret = 0; for (int i = R[head]; i != head; i = R[i]) { if (!vis[i]) { ret++; vis[i] = true; for (int j = D[i]; j != i; j = D[j]) { for (int k = R[j]; k != j; k = R[k]) { vis[CH[k]] = true; } } } } return ret; } void dance(int cnt) { if (cnt + h() >= ans) { //此处写成">"会TLE return ; } if (R[head] == head) { ans = cnt; return ; } int c, Min = oo; for (int i = R[head]; i != head; i = R[i]) { if (S[i] < Min) { Min = S[i]; c = i; } } for (int i = D[c]; i != c; i = D[i]) { remove(i); for (int j = R[i]; j != i; j = R[j]) { remove(j); } dance(cnt + 1); for (int j = L[i]; j != i; j = L[j]) { resume(j); } resume(i); } return ; } int main() { while (scanf("%d%d", &n, &m) != EOF) { totRow = n; totCol = n; initMtx(); build(); ans = oo; dance(0); printf("%d\n", ans); } return 0; }
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