hdu2123 An easy problem (水。)
2012-09-02 09:25
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#include<stdio.h> int main() { int i,j,n,t; scanf("%d",&t); while(t--) { scanf("%d",&n); for(i=1;i<=n;i++) { for(j=1;j<=n;j++) { printf("%d",i*j); if(j!=n)printf(" "); } printf("\n"); } } return 0; }
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