poj2379 Sum of Consecutive Prime Numbers(水)
2012-08-29 00:26
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/* * File: main.cpp * Author: ssslpk * * Created on August 28, 2012, 3:08 PM * * 题目意思: 给出一个数,求这个数有几种方法是由一至多个连续的素数之和 * 解题: 暴力水过 */ #include <cstdlib> #include<iostream> #include<string.h> #include<cstdio> #include<math.h> #define maxn 10002 using namespace std; int ispri[maxn]; int pri[maxn]; int plen; void prime() { memset(ispri,1,sizeof(ispri)); ispri[1]=ispri[0]=0; for(int i=2;i<maxn;i++) { if(ispri[i]) { pri[plen++]=i; for(int j=2;i*j<maxn;j++) ispri[i*j]=0; } } } int main(int argc, char** argv) { prime(); int n; while(scanf("%d",&n),n) { int cnt=0; for(int i=0;i<plen &&pri[i]<=n;i++) { int sum=0; for(int j=0;j<n &&sum<=n;j++)//len { sum+=pri[i+j]; if(sum==n){cnt++;break;} else if(sum>n)break; } } printf("%d\n",cnt); } return 0; }
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