UVA 729 Hamming 距离问题
2012-08-08 14:36
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同上一题类似,全排列A与排列C的区别
没有用STL的 next_permutation
没有用STL的 next_permutation
#include<iostream> #include<cstdio> #include<cstring> #include<memory> #include<queue> #include<algorithm> #include<string> #include<cmath> #include<stack> using namespace std; /// int N, H; int p[20]; int A[20]; void print_permutation(int n, int *A, int *p, int cur) { int i, j; if (cur == n) { for (i = 0; i < n; i++) cout << A[i]; cout << endl; } else for (i = 0; i < n; i++) { if (!i || p[i] != p[i - 1]) { int c1 = 0, c2 = 0; for (j = 0; j < cur; j++) { if (A[j] == p[i]) c1++; } for (j = 0; j < n; j++) { if (p[i] == p[j]) c2++; } if (c1 < c2) { A[cur] = p[i]; print_permutation(n, A, p, cur + 1); } } } } int main() { /// int i, j, k; int nCases; cin >> nCases; while (nCases--) { cin >> N >> H; memset(p, 0, sizeof(p)); j = N - 1; for (i = H; i > 0; i--) p[j--] = 1; print_permutation(N, A, p, 0); if (nCases != 0) cout << endl; } return 0; }
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