【KMP】 hdu1867 A + B for you again
2012-08-02 10:41
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A + B for you again
http://acm.hdu.edu.cn/showproblem.php?pid=1867
Problem DescriptionGenerally speaking, there are a lot of problems about strings processing. Now you encounter another such problem. If you get two strings, such as “asdf” and “sdfg”, the result of the addition between them is “asdfg”, for “sdf” is the tail substring of “asdf”
and the head substring of the “sdfg” . However, the result comes as “asdfghjk”, when you have to add “asdf” and “ghjk” and guarantee the shortest string first, then the minimum lexicographic second, the same rules for other additions.
Input
For each case, there are two strings (the chars selected just form ‘a’ to ‘z’) for you, and each length of theirs won’t exceed 10^5 and won’t be empty.
Output
Print the ultimate string by the book.
Sample Input
asdf sdfg asdf ghjk
Sample Output
asdfg asdfghjk
#include<cstdio> #include<cstring> using namespace std; #define MAX 100005 int next[MAX]; void get_next(char *t) { int i=0,j=-1; next[0]=-1; for(; t[i];) if(j==-1||t[i]==t[j]) { ++i; ++j; next[i]=j; } else j=next[j]; } int kmp(char *s,char *t) { int i=0,j=0; get_next(t); int n=strlen(s),m=strlen(t); for(; i<n&&j<m;) if(j==-1||s[i]==t[j]) ++i,++j; else j=next[j]; if(i>=n) return j; return 0; } int main() { char s[MAX],t[MAX]; for(; ~scanf("%s%s",s,t);) { int x=kmp(s,t); int y=kmp(t,s); if(x==y) { if(strcmp(s,t)>0) { printf("%s",t); printf("%s\n",s+x); } else { printf("%s",s); printf("%s\n",t+x); } } else if(x>y) { printf("%s",s); printf("%s\n",t+x); } else { printf("%s",t); printf("%s\n",s+y); } } return 0; }
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