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UVa 10003 Cutting Sticks

2012-07-28 11:35 399 查看
i, j 为第i个切割点和第j个切割点,

dp[i][j] =min(dp[i][j], dp[i][k] + dp[k][j]) + a[j] - a[i];

这样只要开 52 * 52数组就可以了



#include <cstdio>
#include <cstdlib>
#include <set>
#include <map> 
#include <vector> 
#define N 55 
//看看LLC的优化方法 
using namespace std;

int dp

; 
const int inf =( -1u >> 1) ; 
 int a[52];
void init(int n)
{
      for (int i = 0; i <= n + 1 ; i++)
          for (int j = i + 2; j <= n + 1; j++)
               dp[i][j] = inf;
} 
int main()
{
       int l, n;
       while (scanf("%d", &l) != EOF && l)
       {
             scanf("%d", &n);
             a[0] = 0; 
             for (int i = 1; i <= n; i++)
                  scanf("%d", a+i);
             a[n + 1] = l; 
             for (int i = 0; i <= n; i++)
                  dp[i][i + 1] = 0; 
             init(n);            
             for (int k = 1; k <= n; k++)
                for (int i = 0; i < n  + 1 - k; i++)
                { 
                  for (int j = i + 1; j < (i + k + 1); j++)
                     dp[i][i + k + 1] = min(dp[i][i + k + 1], dp[i][j] + dp[j][i + k + 1]);
                  dp[i][i + k + 1] += (a[i + k + 1] - a[i]);
                }
             printf("The minimum cutting is %d.\n", dp[0][ n + 1]); 
       }
       return 0;
}
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