Kindergarten Counting Game
2012-07-23 13:44
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水题:判断单词有几个
刚开始没仔细想 仅仅判断了空格和空格的个数+1就是单词的个数,后来wa后仔细读读,他说连续的字母是一个单词所以abc!abc这就是两个单词了,还有uva不支持子啊循环中定义变量
刚开始没仔细想 仅仅判断了空格和空格的个数+1就是单词的个数,后来wa后仔细读读,他说连续的字母是一个单词所以abc!abc这就是两个单词了,还有uva不支持子啊循环中定义变量
#include<stdio.h> char str[500]; int Find(int t) { int i; for (i=t;str[i];i++) { if((str[i]>='A' && str[i]<='Z') || (str[i]>='a' && str[i]<='z')) continue; return i; } return i; } int main() { int i; while(gets(str)!=NULL) { int ans=0; for (i=0;str[i];) { if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z') ) { int t=Find(i); ans++; i=t; } else i++; } printf("%d\n",ans); } return 0; }
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