UVA 575 Skew Binary （水题）

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
long long p[64];
int main()
{
long long   i,len,sum;
char num[100];
p[0] = 1;
for(i = 1;i <= 63;i ++)
p[i] = 2*p[i-1];
for(i = 1;i <= 63;i ++)
p[i]--;
while(scanf("%s",num)!=EOF)
{
sum = 0
len = strlen(num);
if(num[0] == '0'&&len == 1)
break;
for(i = 0;i <= len-1;i ++)
{
sum += (num[i]-'0')*p[len-i];
}
printf("%lld\n",sum);
}
return 0;
}