HDU 1076 An Easy Task (水)
2012-05-29 14:54
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An Easy Task
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).
Output
For each test case, you should output the Nth leap year from year Y.
Sample Input
3
2005 25
1855 12
2004 10000
Sample Output
2108
1904
43236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
#include <stdio.h> bool leap(int y){ return y%4==0&&y%100||y%400==0; } int main(){ int y,T,n,cnt,i; scanf("%d",&T); while(T--){ scanf("%d%d",&y,&n); cnt=0; for(i=y;cnt<n;i++) if(leap(i)) cnt++; printf("%d\n",i-1); } return 0; }
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