Sicily 3718 批改作业 （难得水题）

#include <stdio.h>

int main()
{
int n;
int m;
int counter;
int i;
int j;
double sum;
int t;

counter = 0;
scanf("%d %d", &n, &m);
for(i = 0; i < n; i++)
{
sum = 0;
for(j =0; j < m; j++)
{
scanf("%d", &t);
sum += (double)t;
}
if(sum / m < 60)
{
counter++;
}
printf("%.2lf\n", sum / m);
}
printf("%d\n", counter);
return 0;
}