uva-10300 - Ecological Premium
2012-04-18 00:36
302 查看
Problem A
Ecological Premium
Input: standard input
Output: standard output
Time Limit: 1 second
Memory Limit: 32 MB
German farmers are given a premium depending on the conditions at their farmyard. Imagine the following simplified regulation: you know the size of each farmer's farmyard in square meters and the number of animals living at it. We won't make a difference
between different animals, although this is far from reality. Moreover you have information about the degree the farmer uses environment-friendly equipment and practices, expressed in a single integer greater than zero. The amount of money a farmer receives
can be calculated from these parameters as follows. First you need the space a single animal occupies at an average. This value (in square meters) is then multiplied by the parameter that stands for the farmer's environment-friendliness, resulting in the premium
a farmer is paid per animal he owns. To compute the final premium of a farmer just multiply this premium per animal with the number of animals the farmer owns.
Input
The first line of input contains a single positive integer n (<20), the number of test cases. Each test case starts with a line containing a single integerf (0<f<20), the number of farmers in the test case. This line is
followed by one line per farmer containing three positive integers each: the size of the farmyard in square meters, the number of animals he owns and the integer value that expresses the farmer’s environment-friendliness. Input is terminated by end of file.
No integer in the input is greater than100000 or less than
0.
Output
For each test case output one line containing a single integer that holds the summed burden for Germany's budget, which will always be a whole number. Do not output any blank lines.
Sample Input
Sample Output
38
86
7445
#include<stdio.h>
int main()
{
long long n;
long long m,a,b,c,sum,i;
scanf("%lld",&n);
while(n--)
{
sum=0;
scanf("%lld",&m);
for(i=0;i<m;i++)
{
scanf("%lld%lld%lld",&a,&b,&c);
sum+=a*c;
}
printf("%lld\n",sum);
}
}
Ecological Premium
Input: standard input
Output: standard output
Time Limit: 1 second
Memory Limit: 32 MB
German farmers are given a premium depending on the conditions at their farmyard. Imagine the following simplified regulation: you know the size of each farmer's farmyard in square meters and the number of animals living at it. We won't make a difference
between different animals, although this is far from reality. Moreover you have information about the degree the farmer uses environment-friendly equipment and practices, expressed in a single integer greater than zero. The amount of money a farmer receives
can be calculated from these parameters as follows. First you need the space a single animal occupies at an average. This value (in square meters) is then multiplied by the parameter that stands for the farmer's environment-friendliness, resulting in the premium
a farmer is paid per animal he owns. To compute the final premium of a farmer just multiply this premium per animal with the number of animals the farmer owns.
Input
The first line of input contains a single positive integer n (<20), the number of test cases. Each test case starts with a line containing a single integerf (0<f<20), the number of farmers in the test case. This line is
followed by one line per farmer containing three positive integers each: the size of the farmyard in square meters, the number of animals he owns and the integer value that expresses the farmer’s environment-friendliness. Input is terminated by end of file.
No integer in the input is greater than100000 or less than
0.
Output
For each test case output one line containing a single integer that holds the summed burden for Germany's budget, which will always be a whole number. Do not output any blank lines.
Sample Input
3
5
1 1 1
2 2 2
3 3 3
2 3 4
8 9 2
3
9 1 8
6 12 1
8 1 1
3
10 30 40
9 8 5
100 1000 70
Sample Output
38
86
7445
#include<stdio.h>
int main()
{
long long n;
long long m,a,b,c,sum,i;
scanf("%lld",&n);
while(n--)
{
sum=0;
scanf("%lld",&m);
for(i=0;i<m;i++)
{
scanf("%lld%lld%lld",&a,&b,&c);
sum+=a*c;
}
printf("%lld\n",sum);
}
}
相关文章推荐
- [UVa]10300-Ecological Premium
- uva 10300 Ecological Premium
- [解题报告]《算法竞赛入门经典》基础题Volume 0. Getting Started Uva10055 Uva10071 Uva10300 Uva458 Uva494 Uva490 Uva445 Uva488 Uva489 Uva694 Uva457
- 算法竞赛入门经典-前四章-UVa10300 - Ecological Premium-生态奖金-难度0
- UVa10300 - Ecological Premium -难度0
- uva oj 10300
- UVa 10300 - Ecological Premium
- uva 10300 Ecological Premium
- UVA 10300 - Ecological Premium
- UVa 10300 Ecological Premium (water ver.)
- UVA - 10300 Ecological Premium
- UVa10300 Ecological Premium
- UVA - 10300 Ecological Premium(水题)
- uva 10300 - Ecological Premium
- UVA10300(理解题意就容易切)
- acm-UVA10300(水题,纯粹考英语)
- UVA 10300-Ecological Premium
- UVa 10300 - Ecological Premium
- uva10300 Ecological Premium
- UVa 10300 - Ecological Premium