第九周实验报告5
2012-04-17 14:16
309 查看
【任务5】设计一元一次方程类,求形如ax+b=0的方程的解。
例如:输入3x-8=0时,输出的方程的解为x=2.66667;
再如:输入5s+18=0时,输出的方程的解为s=-3.6;
例如:输入3x-8=0时,输出的方程的解为x=2.66667;
再如:输入5s+18=0时,输出的方程的解为s=-3.6;
#include "iostream" using namespace std; class CEquation { private: double a; // 未知数系数 double b; // 常数项 char unknown; // 未知数的符号 public: CEquation(double aa=0,double bb=0); friend istream &operator >> (istream &in,CEquation &e); friend ostream &operator << (ostream &out,CEquation &e); double Solve(); char getUnknown(); }; CEquation::CEquation(double aa,double bb) { a = aa; b = bb; } istream &operator >> (istream &in,CEquation &e) { char n, m ,z; in >> e.a >> e.unknown >> n >> e.b >> m >> z; while( m != '=' || z != '0') { cout <<"输入错误"; in >> e.a >> e.unknown >> n >> e.b >> m >> z; } if( n == '-') { e.b = -e.b ; } return in; } ostream &operator << (ostream &out,CEquation &e) { if( e.b > 0) { out << e.a << e.unknown << "+" << e.b << "=0"; } else { out << e.a << e.unknown << e.b << "=0"; } return out; } double CEquation::Solve() { double c; c = ( -b)/a; return c; } char CEquation::getUnknown() { return unknown; } int main() { CEquation e; cout<<"请输入一元一次方程(输入格式:3x-8=0):"; cin>>e; //在两次测试中,分别输入3x-8=0和5s+18=0 cout<<"方程为:"<<e; cout<<"方程的解为:"<<e.getUnknown()<<"="<<e.Solve()<<endl; //对两次测试,分别输出x=...和s=... e.Solve(); system("pause"); return 0; }