uva 10791【 Minimum Sum LCM】
2012-04-14 17:40
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每做一题就对数学更加崇拜!
看了别人做的才会做的,细节问题不会处理
http://www.mysjtu.com/page/M0/S653/653211.html
还是贴上自己的代码吧。。。
代码如下:
看了别人做的才会做的,细节问题不会处理
http://www.mysjtu.com/page/M0/S653/653211.html
还是贴上自己的代码吧。。。
代码如下:
#include <cstdio> #include <cstring> #include <cmath> int n; long long solve() { int m = (int)sqrt(n + 0.5); long long sum = 0; int count = 0; for(int i = 2;i <= m;i ++) { if(n % i == 0) { int mul = 1; while(n % i == 0) { mul *= i; n = n/i; } sum += mul; count ++; } } if(n != 1 || count == 0) { sum += n; count ++; } if(count == 1) sum ++; return sum; } int main() { int cas = 1; while(scanf("%d",&n) == 1) { if(!n) break; printf("Case %d: ",cas ++); printf("%lld\n",solve()); } return 0; }
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