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HDU 3874 Necklace

2012-04-13 12:16 239 查看
HDU_3874

这个题目和HDU_3333几乎一模一样,具体的思路可以参考我的HDU_3333的题解:/article/4928450.html

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define MAXD 50010
#define MAXQ 200010
long long int sum[4 * MAXD];
int N, Q, a[MAXD], tx[MAXD], X, r[MAXQ], where[MAXD];
struct Question
{
int x, y;
long long int ans;
}question[MAXQ];
int cmpint(const void *_p, const void *_q)
{
int *p = (int *)_p, *q = (int *)_q;
return *p - *q;
}
int cmpq(const void *_p, const void *_q)
{
int *p = (int *)_p, *q = (int *)_q;
return question[*p].y < question[*q].y ? -1 : 1;
}
void init()
{
int i, j, k;
scanf("%d", &N);
for(i = 1; i <= N; i ++)
{
scanf("%d", &a[i]);
tx[i] = a[i];
}
qsort(tx + 1, N, sizeof(tx[0]), cmpint);
X = 0;
for(i = 1; i <= N; i ++)
if(i == 1 || tx[i] != tx[i - 1])
{
where[X] = -1;
tx[X ++] = tx[i];
}
scanf("%d", &Q);
for(i = 0; i < Q; i ++)
{
scanf("%d%d", &question[i].x, &question[i].y);
r[i] = i;
}
qsort(r, Q, sizeof(r[0]), cmpq);
}
void build(int cur, int x, int y)
{
int mid = (x + y) >> 1, ls = cur << 1, rs = (cur << 1) | 1;
sum[cur] = 0;
if(x == y)
return ;
build(ls, x, mid);
build(rs, mid + 1, y);
}
int BS(int x)
{
int min = 0, max = X, mid;
for(;;)
{
mid = (min + max) >> 1;
if(mid == min)
break;
if(tx[mid] <= x)
min = mid;
else
max = mid;
}
return mid;
}
void update(int cur)
{
sum[cur] = sum[cur << 1] + sum[(cur << 1) | 1];
}
void refresh(int cur, int x, int y, int k, int c)
{
int mid = (x + y) >> 1, ls = cur << 1, rs = (cur << 1) | 1;
if(x == y)
{
sum[cur] = c ? a[x] : 0;
return ;
}
if(k <= mid)
refresh(ls, x, mid, k, c);
else
refresh(rs, mid + 1, y, k, c);
update(cur);
}
long long int query(int cur, int x, int y, int s, int t)
{
int mid = (x + y) >> 1, ls = cur << 1, rs = (cur << 1) | 1;
if(x >= s && y <= t)
return sum[cur];
if(mid >= t)
return query(ls, x, mid, s, t);
else if(mid + 1 <= s)
return query(rs, mid + 1, y, s, t);
else
return query(ls, x, mid, s, t) + query(rs, mid + 1, y, s, t);
}
void solve()
{
int i, j, k;
build(1, 1, N);
for(i = 1, j = 0; i <= N; i ++)
{
k = BS(a[i]);
if(where[k] != -1)
refresh(1, 1, N, where[k], 0);
where[k] = i;
refresh(1, 1, N, i, 1);
while(j < Q && question[r[j]].y == i)
{
question[r[j]].ans = query(1, 1, N, question[r[j]].x, question[r[j]].y);
++ j;
}
}
for(i = 0; i < Q; i ++)
printf("%I64d\n", question[i].ans);
}
int main()
{
int t;
scanf("%d", &t);
while(t --)
{
init();
solve();
}
return 0;
}
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