第八周任务3
2012-04-11 21:29
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#include<iostream.h> int gcd(int m, int n); class CFraction { private: int nume; // 分子 int deno; // 分母 public: //构造函数及运算符重载的函数声明 CFraction(int nu=0,int de=1); //构造函数,初始化用 void Simplify(); //化简(使分子分母没有公因子) void output(); bool operator > (CFraction &t); bool operator < (CFraction &t); bool operator >= (CFraction &t); bool operator <= (CFraction &t); bool operator == (CFraction &t); bool operator != (CFraction &t); CFraction operator+(CFraction &c); CFraction operator-(CFraction &c); CFraction operator*(CFraction &c); CFraction operator/(CFraction &c); CFraction operator-(); friend CFraction operator+(CFraction &c1,const double &d); friend CFraction operator+(const double &d, CFraction &c); friend CFraction operator*(const double &d,CFraction &c); CFraction operator/(const double &d); CFraction operator*(const double &d); friend CFraction operator/(const double &d,CFraction &c); }; CFraction::CFraction(int nu,int de) //构造函数,初始化用 { if (de!=0) { nume=nu; deno=de; } else { cerr<<"初始化中发生错误,程序退出\n"; // system("pause"); // exit(0); } } void CFraction::Simplify() //化简(使分子分母没有公因子) { int n; if(nume < 0) { n = gcd(-nume, deno); } else { n = gcd(nume, deno); } nume = nume / n; deno = deno / n; } // 求m,n的最大公约数 int gcd(int m, int n) { int r; if (m<n){r=m;m=n;n=r;} while(r=m%n) // 求m,n的最大公约数 { m=n; n=r; } return n; } void CFraction::output() { cout<<nume<<'/'<<deno<<endl; } bool CFraction::operator > (CFraction &t) { CFraction c2,c3; c2.nume =nume*t.deno ; c3.nume =t.nume *deno; if(c2.nume >c3.nume ) return true; else return false; } bool CFraction::operator < (CFraction &t) { CFraction c2,c3; c2.nume =nume*t.deno ; c3.nume =t.nume *deno; if(c2.nume <c3.nume ) return true; else return false; } bool CFraction::operator >= (CFraction &t) { CFraction c1; c1.nume =nume; c1.deno =deno; if (c1<t) return false; return true; } bool CFraction::operator <= (CFraction &t) { CFraction c1; c1.nume =nume; c1.deno =deno; if (c1>t) return false; return true; } bool CFraction::operator == (CFraction &t) { CFraction c1; c1.nume =nume; c1.deno =deno; if (c1<t) return false; if (c1>t) return false; return false; } bool CFraction::operator != (CFraction &t) { CFraction c1; c1.nume =nume; c1.deno =deno; if (c1==t) return false; return true; } CFraction CFraction::operator+(CFraction &c) { CFraction c2,c3,c4; c2.nume =nume*c.deno ; c3.nume =c.nume *deno; c2.deno =deno*c.deno ; c3.deno =c.deno *deno; c4.nume=c2.nume +c3.nume ; c4.deno =c2.deno ; c4.Simplify (); return c4; } CFraction CFraction::operator-(CFraction &c) { CFraction c2,c3,c4; c2.nume =nume*c.deno ; c3.nume =c.nume *deno; c2.deno =deno*c.deno ; c3.deno =c.deno *deno; c4.nume=c2.nume -c3.nume ; c4.deno =c2.deno ; c4.Simplify (); return c4; } CFraction CFraction::operator*(CFraction &c) { CFraction c2,c3,c4; c2.nume =nume*c.nume ; c2.deno =deno*c.deno ; c2.Simplify (); return c2; } CFraction CFraction::operator/(CFraction &c) { CFraction c2,c3; c2.nume =c.deno ; c2.deno =c.nume ; c3.nume =nume*c2.nume ; c3.deno =deno*c2.deno ; c3.Simplify (); return c3; } CFraction CFraction::operator-() { CFraction c2; c2.nume =nume; c2.deno =deno; c2.Simplify (); if(c2.nume<0 || c2.deno<0) { if(c2.nume <0) { c2.nume =-nume; } else { c2.deno =-deno; } } else { c2.nume =-nume; c2.deno =deno; } return c2; } CFraction operator+(CFraction &c1,const double &d) { CFraction c; c.nume =d*c1.nume +c1.nume ; c.deno =c1.deno ; c.Simplify (); return c; } CFraction operator+(const double &d, CFraction &c) { CFraction c1; c1.nume =d*c.nume +c.nume ; c1.deno =c.deno ; c1.Simplify (); return c1; } CFraction operator*(const double &d,CFraction &c) { CFraction c1; c1.nume =d*c.nume; c1.deno =c.deno ; c1.Simplify (); return c1; } CFraction CFraction:: operator/(const double &d) { CFraction c; c.nume =nume; c.deno =deno*d ; c.Simplify (); return c; } CFraction CFraction:: operator*(const double &d) { CFraction c; c.nume =d*nume ; c.deno =deno ; c.Simplify (); return c; } CFraction operator/(const double &d,CFraction &c) { CFraction c1; c1.nume =d*c.deno ; c1.deno =c.nume ; c1.Simplify (); return c1; } //用于测试的main()函数 void main() { CFraction c1(8,20),c2(11,20),c; double d=5; cout<<"c1为:"; c1.output(); cout<<"c2为:"; c2.output(); cout<<"下面比较两个时间大小:\n"; if (c1>c2) cout<<"c1>c2"<<endl; if (c1<c2) cout<<"c1<c2"<<endl; if (c1==c2) cout<<"c1=c2"<<endl; if (c1!=c2) cout<<"c1≠c2"<<endl; if (c1>=c2) cout<<"c1≥c2"<<endl; if (c1<=c2) cout<<"c1≤c2"<<endl; cout<<endl; cout<<"c1+c2的数值为:"; c=c1+c2; c.output(); cout<<endl; cout<<"c1-c2的数值为:"; c=c1-c2; c.output(); cout<<endl; cout<<"c1*c2的数值为:"; c=c1*c2; c.output(); cout<<endl; cout<<"c1/c2的数值为:"; c=c1/c2; c.output(); cout<<endl; cout<<"对c1取反的结果为:"; c=-c1; c.output (); cout<<endl; cout<<"c1+d的值为:"; c=c1+d; c.output (); cout<<"d+c1的值为:"; c=d+c1; c.output (); cout<<endl; cout<<"5+c1的值为:"; c=5+c1; c.output (); cout<<endl; cout<<"c1*2的值为:"; c=c1*2; c.output (); cout<<"2*c1的值为:"; c=2*c1; c.output (); cout<<"5/c1的值为:"; c=5/c1; c.output (); cout<<"c1/5的值为:"; c=c1/5; c.output (); //system("PAUSE"); }
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