您的位置:首页 > 其它

第八周作业 1.3

2012-04-11 09:03 176 查看
/* (程序头部注释开始)

* 程序的版权和版本声明部分

* Copyright (c) 2011, 烟台大学计算机学院学生 

* All rights reserved.

* 文件名称:                              

* 作    者: 孙建朋                   

* 完成日期: 2012 年 4 月 11 日

* 版 本 号: 2012041101         

 

* 对任务及求解方法的描述部分

* 输入描述: 

* 问题描述: 

* 程序输出: 

* 程序头部的注释结束

*/


#include<iostream>
using namespace std;
class Complex
{
public:
Complex(){real=0;imag=0;}
Complex(double r,double i){real=r;imag=i;}
friend Complex operator+(Complex &c1,Complex &c2);//声明重载函数加作为友元函数
friend Complex operator-(Complex &c1,Complex &c2);//声明重载函数减作为友元函数
friend Complex operator*(Complex &c1,Complex &c2);//声明重载函数加乘作为友元函数
friend Complex operator/(Complex &c1,Complex &c2);//声明重载函数除作为友元函数
friend Complex operator+(Complex &c1,double &d); //声明重载函数第一个参数可以不是类对象,在用double型中或用double d;又或const double &d
friend Complex operator+(double &d,Complex &c1);//声明重载函数第二个参数可以不是类对象
friend Complex operator-(Complex &c2);//声明一目运算符形如"-c"
void display();
private:
double real;
double imag;
};
//定义友元函数加法
Complex operator+(Complex &c1,Complex &c2)
{
return Complex(c1.real + c2.real,c1.imag + c2.imag);
}
//定义复数加double型的数
Complex operator+(Complex &c1,double &d)
{
return Complex(c1.real + d,c1.imag);
}
Complex operator+(double &d,Complex &c1)
{
return Complex(c1.real + d,c1.imag);
}
//定义友元函数减法
Complex operator-(Complex &c1,Complex &c2)
{
return Complex(c1.real - c2.real,c1.imag - c2.imag);
}
//定义一目运算符形如"-c"
Complex operator-(Complex &c2)
{
return Complex(-c2.real, -c2.imag);
}
//定义友元函数乘法
Complex operator*(Complex &c1,Complex &c2)
{
Complex c;
c.real = c1.real*c2.real - c1.imag*c2.imag;
c.imag = c1.real*c2.imag + c1.imag*c2.real;
return c;
}
//定义友元函数除法
Complex operator/(Complex &c1,Complex &c2)
{
Complex c;
c.real = (c1.real*c2.real + c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
c.imag = (-c1.real*c2.imag + c1.imag*c2.real)/(c2.real*c2.real+c2.imag*c2.imag);
return c;
}
void Complex::display()
{
cout<<"("<<real<<","<<imag<<"i)"<<endl;
}
int main()
{
double m=2.15;//用 const 或直接用d就不用再定义这个啦!直接在后面用2.15就行
Complex c1(3,4),c2(5,-10),c3;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
c3=c1+c2;
cout<<"c1+c2=";
c3.display();
c3=c1-c2;
cout<<"c1-c2=";
c3.display();
c3=c1*c2;
cout<<"c1*c2=";
c3.display();
c3=c1/c2;
cout<<"c1/c2=";
c3.display();
c3=m+c1;
cout<<"2.15+c1=";
c3.display();
c3=c1+m;
cout<<"c1+2.15=";
c3.display();
c3=-c2;
cout<<"-c2=";
c3.display();
system("pause");
return 0;
}


 

 
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  作业 c system 任务