第八周实验报告4

/* (程序头部注释开始)

* 程序的版权和版本声明部分

* Copyright (c) 2011, 烟台大学计算机学院学生

* All rights reserved.

* 文件名称：                             

* 作    者：         赵桐辉                    

* 完成日期：         2012年4  月9     日

* 版 本 号：         
* 对任务及求解方法的描述部分

* 输入描述：

* 问题描述： 在任务3的基础上拓展。分数类中的对象可以和整型数进行四则运算，且运算符合交换律。例如：CFraction a(1,3),b; int i=2; 可以完成b=a+i;。同样，可以完成i+a, 45+a, a*27, 5/a等各种运算。

* 程序输出：

* 程序头部的注释结束

*/

#include<iostream>
using namespace std;

int gcd(int m, int n);

class CFraction
{
private:
int nume;  // 分子
int deno;  // 分母
public:
//构造函数及运算符重载的函数声明
CFraction(int nu=0,int de=1);   //构造函数，初始化用
void Simplify();                    //化简（使分子分母没有公因子）
void output();
bool operator > (CFraction &t);
bool operator < (CFraction &t);
bool operator >= (CFraction &t);
bool operator <= (CFraction &t);
bool operator == (CFraction &t);
bool operator != (CFraction &t);
CFraction operator+(CFraction &c);
CFraction operator-(CFraction &c);
CFraction operator*(CFraction &c);
CFraction operator/(CFraction &c);
CFraction operator-();
friend CFraction operator+(CFraction &c1,const double &d);
friend CFraction operator+(const double &d, CFraction &c);
friend CFraction operator*(const double &d,CFraction &c);
CFraction operator/(const double &d);
CFraction operator*(const double &d);
friend CFraction operator/(const double &d,CFraction &c);
};
CFraction::CFraction(int nu,int de)   //构造函数，初始化用
{
if (de!=0)
{
nume=nu;
deno=de;
}
else
{
cerr<<"初始化中发生错误，程序退出\n";
//	system("pause");
//	exit(0);
}
}
void CFraction::Simplify()                    //化简（使分子分母没有公因子）
{
int n;
if(nume < 0)
{
n = gcd(-nume, deno);
}
else
{
n = gcd(nume, deno);
}

nume = nume / n;

deno = deno / n;
}
// 求m，n的最大公约数
int gcd(int m, int n)
{
int p;
if (m<n){p=m;m=n;n=p;}
while(p=m%n)  // 求m，n的最大公约数
{
m=n;
n=p;
}
return n;
}

void CFraction::output()
{
cout<<nume<<'/'<<deno<<endl;
}
bool CFraction::operator > (CFraction &t)
{
CFraction c2,c3;
c2.nume =nume*t.deno ;
c3.nume =t.nume *deno;
if(c2.nume >c3.nume )
return true;
else
return false;
}
bool CFraction::operator < (CFraction &t)
{
CFraction c2,c3;
c2.nume =nume*t.deno ;
c3.nume =t.nume *deno;
if(c2.nume <c3.nume )
return true;
else
return false;
}
bool CFraction::operator >= (CFraction &t)
{
CFraction c1;
c1.nume =nume;
c1.deno =deno;
if (c1<t)
return false;
return true;
}

bool CFraction::operator <= (CFraction &t)
{
CFraction c1;
c1.nume =nume;
c1.deno =deno;
if (c1>t)
return false;
return true;
}
bool CFraction::operator == (CFraction &t)
{
CFraction c1;
c1.nume =nume;
c1.deno =deno;
if (c1<t)
return false;
if (c1>t)
return false;
return false;
}

bool CFraction::operator != (CFraction &t)
{
CFraction c1;
c1.nume =nume;
c1.deno =deno;
if (c1==t)
return false;
return true;
}
CFraction CFraction::operator+(CFraction &c)
{
CFraction c2,c3,c4;
c2.nume =nume*c.deno ;
c3.nume =c.nume *deno;
c2.deno =deno*c.deno ;
c3.deno =c.deno *deno;
c4.nume=c2.nume +c3.nume ;
c4.deno =c2.deno ;
c4.Simplify ();
return c4;
}
CFraction CFraction::operator-(CFraction &c)
{
CFraction c2,c3,c4;
c2.nume =nume*c.deno ;
c3.nume =c.nume *deno;
c2.deno =deno*c.deno ;
c3.deno =c.deno *deno;
c4.nume=c2.nume -c3.nume ;
c4.deno =c2.deno ;
c4.Simplify ();
return c4;
}
CFraction CFraction::operator*(CFraction &c)
{
CFraction c2,c3,c4;
c2.nume =nume*c.nume  ;
c2.deno =deno*c.deno ;
c2.Simplify ();
return c2;
}
CFraction CFraction::operator/(CFraction &c)
{
CFraction c2,c3;
c2.nume =c.deno ;
c2.deno =c.nume ;
c3.nume =nume*c2.nume ;
c3.deno =deno*c2.deno ;
c3.Simplify ();
return c3;
}
CFraction CFraction::operator-()
{
CFraction c2;
c2.nume =nume;
c2.deno =deno;
c2.Simplify ();
if(c2.nume<0 || c2.deno<0)
{
if(c2.nume <0)
{
c2.nume =-nume;
}
else
{
c2.deno =-deno;
}
}
else
{
c2.nume =-nume;
c2.deno =deno;
}
return c2;
}
CFraction operator+(CFraction &c1,const double &d)
{
CFraction c;
c.nume =d*c1.nume +c1.nume ;
c.deno =c1.deno ;
c.Simplify ();
return c;

}
CFraction operator+(const double &d, CFraction &c)
{
CFraction c1;
c1.nume =d*c.nume +c.nume ;
c1.deno =c.deno ;
c1.Simplify ();
return c1;
}
CFraction operator*(const double &d,CFraction &c)
{
CFraction c1;
c1.nume =d*c.nume;
c1.deno =c.deno ;
c1.Simplify ();
return c1;
}
CFraction CFraction:: operator/(const double &d)
{
CFraction c;
c.nume =nume;
c.deno =deno*d ;
c.Simplify ();
return c;
}
CFraction CFraction:: operator*(const double &d)
{
CFraction c;
c.nume =d*nume ;
c.deno =deno ;
c.Simplify ();
return c;
}
CFraction operator/(const double &d,CFraction &c)
{
CFraction c1;
c1.nume =d*c.deno ;
c1.deno =c.nume ;
c1.Simplify ();
return c1;
}
//用于测试的main()函数
void main()
{
CFraction c1(8,20),c2(11,20),c;
double d=5;
cout<<"c1为：";
c1.output();
cout<<"c2为：";
c2.output();
cout<<"下面比较两个时间大小：\n";
if (c1>c2) cout<<"c1>c2"<<endl;
if (c1<c2) cout<<"c1<c2"<<endl;
if (c1==c2) cout<<"c1＝c2"<<endl;
if (c1!=c2) cout<<"c1≠c2"<<endl;
if (c1>=c2) cout<<"c1≥c2"<<endl;
if (c1<=c2) cout<<"c1≤c2"<<endl;
cout<<endl;
cout<<"c1+c2的数值为：";
c=c1+c2;
c.output();
cout<<endl;
cout<<"c1-c2的数值为：";
c=c1-c2;
c.output();
cout<<endl;
cout<<"c1*c2的数值为：";
c=c1*c2;
c.output();
cout<<endl;
cout<<"c1/c2的数值为：";
c=c1/c2;
c.output();
cout<<endl;
cout<<"对c1取反的结果为：";
c=-c1;
c.output ();
cout<<endl;
cout<<"c1+d的值为：";
c=c1+d;
c.output ();
cout<<"d+c1的值为：";
c=d+c1;
c.output ();
cout<<endl;
cout<<"5+c1的值为：";
c=5+c1;
c.output ();
cout<<endl;
cout<<"c1*2的值为：";
c=c1*2;
c.output ();
cout<<"2*c1的值为：";
c=2*c1;
c.output ();
cout<<"5/c1的值为：";
c=5/c1;
c.output ();
cout<<"c1/5的值为：";
c=c1/5;
c.output ();

//system("PAUSE");
}

上级感言：初步学会了运算符重载的用法