zoj 2850 Beautiful Meadow
2012-04-04 11:06
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//简单题,就是对给出的两个条件进行判断即可! #include "iostream" using namespace std; int meadow[15][15]; int main() { int i, j, N, M; bool flag1, flag2; while (cin >> N >> M && N && M) { flag1 = flag2 = false; for (i = 0; i < 15; i++) for (j = 0; j < 15; j++) meadow[i][j] = 2; for (i = 0; i < N; i++) for (j = 0; j < M; j++) cin >> meadow[i][j]; //第一种情况的搜索! for (i = 0; i < N; i++) { if (flag1) break; for (j = 0; j < M; j++) { if (meadow[i][j] != 1) { flag1 = true; break; } } } //第二种情况的搜索! for (i = 0; i < N; i++) { if (flag2) break; for (j = 0; j < M; j++) { if(meadow[i][j] == 0) { if (meadow[i][j+1] == 0 || meadow[i+1][j] == 0) { flag2 = true; break; } } } } if (!flag1 || flag2) cout << "No" << endl; else cout << "Yes" << endl; } }
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