iphone 传入两个经纬度,计算经纬度之间的距离
2012-03-23 14:43
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传入两个经纬度,计算经纬度之间的距离:
+(double)LantitudeLongitudeDist:(double)lon1 lat1:(double)lat1 lon2:(double)lon2 lat2:(double)lat2 { double er = 6378137; // 6378700.0f; double radlat1 = PI*lat1/180.0f; double radlat2 = PI*lat2/180.0f; //now long. double radlong1 = PI*lon1/180.0f; double radlong2 = PI*lon2/180.0f; if( radlat1 < 0 ) radlat1 = PI/2 + fabs(radlat1);// south if( radlat1 > 0 ) radlat1 = PI/2 - fabs(radlat1);// north if( radlong1 < 0 ) radlong1 = PI*2 - fabs(radlong1);//west if( radlat2 < 0 ) radlat2 = PI/2 + fabs(radlat2);// south if( radlat2 > 0 ) radlat2 = PI/2 - fabs(radlat2);// north if( radlong2 < 0 ) radlong2 = PI*2 - fabs(radlong2);// west //spherical coordinates x=r*cos(ag)sin(at), y=r*sin(ag)*sin(at), z=r*cos(at) //zero ag is up so reverse lat double x1 = er * cos(radlong1) * sin(radlat1); double y1 = er * sin(radlong1) * sin(radlat1); double z1 = er * cos(radlat1); double x2 = er * cos(radlong2) * sin(radlat2); double y2 = er * sin(radlong2) * sin(radlat2); double z2 = er * cos(radlat2); double d = sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)+(z1-z2)*(z1-z2)); //side, side, side, law of cosines and arccos double theta = acos((er*er+er*er-d*d)/(2*er*er)); double dist = theta*er; return dist; }
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