用c#向SQL Server中存储图片并且再从数据库中读取图片

在WinForm中，使C#语言向SQL Server（2005）存储图片并且将图片从数据库中读取出来，显示在窗体中

步骤：

1.首先，在SQL Server中创建一个表，用来存储图片；

示例代码：
use tempdb

go

if exists (select * from sysobjects where name = 'Images')

drop table Images

go

create table Images

(

 BLODID int identity not null,

 BLOBData image not null

)

2.打开Visual Studio2005，创建一个WinForm应用程序。向Form1中添加一个PictureBox控件，再添加两个

Button控件，将Button1的Text属性分别设为"保存图片"，"显示图片"；

3.在Form1的代码之中，首先引入命名空间：

    using System.Data.SqlCilent;

    using System.IO;

    using System.Drawing.Imaging;

4.编写"保存图片"按钮的单击事件，用于保存图片；

示例代码：
private void button1_Click(object sender, EventArgs e)

        {

           

            try

            {

                string strConn = "Server=.;DataBase=tempdb;Integrated Security=true";

                SqlConnection connection = new SqlConnection(strConn);

                string sql = "insert into blobtest (blobdata) values (@blobdata)";

                SqlCommand command = new SqlCommand(sql, connection);

                //图片路径

                string picturePath = @"D:\pic.jpg";  //注意，这里需要指定保存图片的绝对路径和图片 

                                               //文件的名称，每次必须更换图片的名称，这里很为不便

                //创建FileStream对象

                FileStream fs = new FileStream(picturePath, FileMode.Open, FileAccess.Read);

                //声明Byte数组

                Byte[] mybyte = new byte[fs.Length];

                //读取数据

                fs.Read(mybyte,0,mybyte.Length);

                fs.Close();

                //转换成二进制数据，并保存到数据库

                SqlParameter prm = new SqlParameter

("@blobdata",SqlDbType.VarBinary,mybyte.Length,ParameterDirection.Input,false,0,0,null,DataRowVers

ion.Current,mybyte);

                command.Parameters.Add(prm);

                //打开数据库连接

                connection.Open();

                command.ExecuteNonQuery();

                connection.Close();

            }

            catch (Exception ex)

            {

                MessageBox.Show(ex.Message);

            }

        }

5.编写"显示图片"的单击事件，将图片从数据库中读取出来显示在PictureBox之中

示例代码：
private void button2_Click(object sender, EventArgs e)

        {

            try

            {

                //创建数据库连接字符串

                string strConn = "Server=.;DataBase=tempdb;Integrated Security=True";

                //创建SqlConnection对象

                SqlConnection connection = new SqlConnection(strConn);

                //打开数据库连接

                connection.Open();

                //创建SQL语句

                string sql = "select blodid,blobdata from blobtest order by blodid";

                //创建SqlCommand对象

                SqlCommand command = new SqlCommand(sql,connection);

                //创建DataAdapter对象

                SqlDataAdapter dataAdapter = new SqlDataAdapter(command);

                //创建DataSet对象

                DataSet dataSet = new DataSet();

                dataAdapter.Fill(dataSet, "BLOBTest");

                int c = dataSet.Tables["BLOBTest"].Rows.Count;

                if (c > 0)

                {

                    Byte[] mybyte = new byte[0];

                    mybyte = (Byte[])(dataSet.Tables["BLOBTest"].Rows[c-1]["BLOBData"]);

                    MemoryStream ms = new MemoryStream(mybyte);

                    pictureBox1.Image = Image.FromStream(ms);

                }

                connection.Close();

            }

            catch (Exception ex)

            {

                MessageBox.Show(ex.Message);

            }

        }

这样就可以实现用c#语言向SQL Server中保存图片，并从数据库中读取图片显示在窗体之中了···