UVa 10300 Ecological Premium
2012-01-23 10:19
281 查看
题目的意思是计算每个动物的平均占地,之后乘以环境友好程度在乘以动物数量,计算这些数值的和输出。其实就是:面积乘上环境友好程度!绕了这么大的弯……不过可笑的是我一开始没有看出来,对英文题还是不熟悉……
代码如下:
代码如下:
#include<stdio.h> int main() { long n; scanf("%ld",&n); for(long cas=1;cas<=n;cas++) { long f,size,animal,ef,ans=0; scanf("%ld",&f); for(long i=1;i<=f;i++) { scanf("%ld%ld%ld",&size,&animal,&ef); ans+=size*ef; } printf("%ld\n",ans); } return 0; }
相关文章推荐
- UVA 10300 - Ecological Premium
- UVa 10300 Ecological Premium (water ver.)
- UVA - 10300 Ecological Premium(水题)
- UVA - 10300 Ecological Premium
- UVa10300 Ecological Premium
- UVA10300(理解题意就容易切)
- uva 10300 - Ecological Premium
- acm-UVA10300(水题,纯粹考英语)
- UVA 10300-Ecological Premium
- UVa 10300 - Ecological Premium
- uva-10300 - Ecological Premium
- UVa 10300 - Ecological Premium
- uva10300 Ecological Premium
- UVA 10300
- Ecological Premium - UVa10300
- Uva10300
- Ecological Premium - UVa10300
- UVA:10300 - Ecological Premium
- UVa 10300 Ecological Premium(生态奖金)
- UVA oj 10300 Ecological Premium(水题)