SGU 113 Nearly prime numbers
2012-01-11 22:09
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SGU_113
对数分解素因子即可,如果最后素因子的个数为1或者大于2自然无解。
对数分解素因子即可,如果最后素因子的个数为1或者大于2自然无解。
#include<stdio.h> #include<string.h> #include<math.h> #define MAXD 100010 #define D 100000 int isprime[MAXD]; int N; void prepare() { long long int i, j; memset(isprime, -1, sizeof(isprime)); for(i = 2; i < D; i ++) if(isprime[i]) for(j = i * i; j < D; j += i) isprime[j] = 0; } int check(int x) { int i, k, ok, num = 0; while(x != 1 && num <= 2) { k = (int)sqrt(x + 1.0); for(i = 2; i <= k; i ++) if(isprime[i] && x % i == 0) { ++ num; x /= i; break; } if(i == k + 1) { ++ num; x /= x; } } if(num == 2) return 1; else return 0; } int main() { int i, x; prepare(); scanf("%d", &N); for(i = 0; i < N; i ++) { scanf("%d", &x); if(x < 2 || !check(x)) printf("No\n"); else printf("Yes\n"); } return 0; }
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