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ZOJ2297 Survival,压缩状态DP

2012-01-05 21:21 120 查看
算是经典的压缩状态DP吧,枚举每一种状态,再枚举对手

/*******************************************************************************
# Author : Neo Fung
# Email : neosfung@gmail.com
# Last modified: 2012-01-05 21:22
# Filename: ZOJ2297 Survival.cpp
# Description :
******************************************************************************/
// #include "stdafx.h"
// #define DEBUG

#include <fstream>
#include <stdio.h>
#include <iostream>
#include <string.h>
#include <string>
#include <memory.h>
#include <limits.h>
#include <algorithm>
#include <math.h>
#include <numeric>
#include <functional>
#include <ctype.h>
#define MAX 22
#define MAX_LEN 1<<22
using namespace std;

int consume[MAX],recovered[MAX],dp[MAX_LEN];

int main(void)
{
#ifdef DEBUG
freopen("C:/Users/neo/Desktop/stdin.txt","r",stdin);
freopen("C:/Users/neo/Desktop/stdout.txt","w",stdout);
#endif
int n;
int orichi;

while(~scanf("%d",&n))
{
--n;
memset(dp,0,sizeof(dp));
for(int i=0;i<n;++i)
{
scanf("%d%d",&consume[i],&recovered[i]);
}
dp[0]=100;
scanf("%d",&orichi);
int max_len=1<<n;

for(int j=0;j<max_len;++j)
for(int i=0;i<n ;++i)
{
int temp=1<<i;
if(!(j&temp))
if(dp[j]-consume[i]>=0)
{
dp[j|temp]=max( dp[j|temp] , dp[j]-consume[i]+recovered[i]);
dp[j|temp]=min(100,dp[j|temp]);
}
}
if( dp[max_len-1]-orichi>=0)
printf("clear!!!\n");
else
printf("try again\n");
}

return 0;
}
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