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修正android 处理连续按键两次

2011-11-15 18:01 176 查看
1.变量初始化：

private  boolean isExit = false;
private  boolean hasTask = false;
2.按键捕捉（比如放在onTouchDown函数中进行按键监听

PressHomeKeyCount localHandler = new PressHomeKeyCount();

if(isExit == false ) {
isExit = true;
if(!hasTask) {
Message localMessage = new Message();
localMessage.what = 0;
localHandler.sendEmptyMessageDelayed(localMessage.what, 500L);
}
else{
if(mRecentApplication.getVisibility() == View.VISIBLE){
mRecentApplication.setVisibility(View.INVISIBLE);
isExit = false;
hasTask = false;
}
}
}
else{
if(mRecentApplication.getVisibility() == View.INVISIBLE){
mRecentApplication.setVisibility(View.VISIBLE);
}
}


3.Handle对象

public class PressHomeKeyCount extends Handler {
public void handleMessage(final Message msg) {
isExit = false;
hasTask = true;
}
}


上边的做法会出现死循环，我又对它进行了改进，以下是改进后的代码，经过测试没什么问题，其中变量初始化一样

2.按键捕捉

if(isExit == false ) {
isExit = true;
if(!hasTask) {
Message localMessage = new Message();
localMessage.what = 0;
localHandler.sendEmptyMessageDelayed(localMessage.what, 500L);
}
else{
isExit = false;
hasTask = false;
localHandler.removeMessages(0);

if(mRecentApplication.getVisibility() == View.VISIBLE){
mRecentApplication.setVisibility(View.INVISIBLE);
}
}
}
else{
if(mRecentApplication.getVisibility() == View.INVISIBLE){
mRecentApplication.setVisibility(View.VISIBLE);
}
localHandler.removeMessages(0);
isExit = false;
hasTask = true;
}



3.Handler对象

public class PressHomeKeyCount extends Handler {
public void handleMessage(final Message msg) {
isExit = false;
hasTask = false;
}
}

                                            

                                        

                        
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                                                android
                                                class
                                                测试
                                                

                        

                    


                

            


            

                
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