[USACO 4.4.1 Shuttle Puzzle]
2011-10-29 18:13
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[题目来源]:USACO 4.4.1
[关键字]:数学
[题目大意]:一个1*2n+1的棋盘,左边有n个白子,中间一个空格,右边n个黑子,求出将其交换的步骤。
//==========================================================================================================
[分析]:http://www.nocow.cn/index.php/USACO/shuttle
[代码]:
View Code
[关键字]:数学
[题目大意]:一个1*2n+1的棋盘,左边有n个白子,中间一个空格,右边n个黑子,求出将其交换的步骤。
//==========================================================================================================
[分析]:http://www.nocow.cn/index.php/USACO/shuttle
[代码]:
View Code
{ ID:x yr; PROB:shuttle LANG:PASCAL } var n, s: longint; a: array[0..200] of longint; procedure init; var i, c: longint; begin readln(n); s := 4; i := 1; c := 5; while i < n do begin s := s+c; inc(i); inc(c,2); end; //writeln(s); //readln; end; procedure work; var i, l, c1, c2: longint; begin i := 1; l := 1; c1 := -1; c2 := 2; while i <= s div 2 do begin a[i] := c1; for i := i+1 to i+l do a[i] := c2; inc(l); c1 := -c1; c2 := -c2; inc(i); end; c1 := 0; l := s div 2; if not odd(n) then begin inc(l); inc(c1); end; for i := l to s do begin a[i] := a[i-c1]; inc(c1,2); end; //for i := 1 to s do write(a[i],''); //readln; l := n+1; for i := 1 to s-2 do begin l := l+a[i]; if i mod 20 = 0 then writeln(l) else write(l,''); end; l := l+a[s-1]; writeln(l); //readln; end; begin assign(input,'shuttle.in');reset(input); assign(output,'shuttle.out');rewrite(output); init; work; close(input); close(output); end.
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