C语言实现检查单词是否为变位词(相同字母的重新排列)

#include<stdio.h>
int main()
{
int a[26]={0},i=0,n=0,j=0;
int arr[20]={0};
char ch='\0';
printf("Enter first word:");
ch=getchar();
while(ch != '\n')
{   if(ch>='A' && ch<='Z')
arr[i++]=ch-'A';
else
arr[i++]=ch-'a';
ch=getchar();
}
arr[i]=0;

for(n=0;n<i;n++)
{
if(a[arr
])
{
a[arr
]++;
continue;
}
a[arr
]=1;
}
/*
for(n=0;n<26;n++)
{
printf("%c,%d\n",n+'a',a
);
}
*/
printf("Enter the second word:");
ch=getchar();
while(ch != '\n')
{   if(ch>='A' && ch<='Z')
{
ch=ch-'A';
a[ch]--;
}
else
{
ch=ch-'a';
a[ch]--;
}
ch=getchar();
}
for(j=0;j<26;j++)
{
if(a[j]!=0)
{
printf("The words are not anagrams.");
break;
}
else
{
continue;
}
}
if(j==26)
{
printf("The words are anagrams.");
}
getch();
}