Struts2标签迭代数组汇总

1.一维数组

<s:iterator value="#request.headers" id="head" status="i">

<td>${i.count}</td>

<td>${head}</td>

</s:iterator>

<select class="select1" tabindex="2" id="selectname3" name="selectname3" >

<s:iterator status="status" value="#request.select_acct"

id="item" >

<option value="item" />

<s:property value='item' />

</option>

</s:iterator>

</select>

2.list

<s:iterator value= "{'1','2','3','4','5'}" id= 'number' >

<s:property value= 'number' />

</s:iterator

3.map

<s:iterator value= "map" id= "id" status= "st" >

key : <s:property value= 'key' />

value:<s:property vlaue= 'value' />

</s:iterator>

4：遍历数据栈.简单的List类，

List<Attr>

class Attr{String attrName;String getAttrName(){return "123";}}

<s:iterator value= "label" id= "id" >

<s:property value= "#id.attrName" />

</s:iterator>

5：遍历2个list；

List<AttrName> attrN {color,size,style}

List<AttrValue> attrV {red,20,gay}

这2个list的元素是一一对应的，一个attrN对应一个attrV

< s:iterator value = "%{attrN }" id = "id" status = "status" >

index is : < s:property value = 'status.index' />

attrName is : < s:property value = 'id' /> or < s:property value = '%{id}' />

attrName is : < s:property value = '%{attrV[#status.index]}' />

</ s:iterator >

6.二维数组

struts2中二维数组的显示

1、用两重循环的方法

<s:iterator id="data1" value="#request.data" status="d1">

<s:iterator id="data2" value="#request.data1" status="d2">

<s:property value="#data2"/>

</s:iterator>

</s:iterator>

2、用一重循环的方法

<s:iterator value="collection1" status="status">

<s:property value="collection1[#status.index][0]"/>

<s:property value="collection1[#status.index][1]"/>

</s:iterator>