hdu acm steps 2.2.7

#include <stdio.h>

int fib[50]={1,1,1};
int main()
{
    int a,b,n,i;
    while(scanf("%d%d%d",&a,&b,&n)!=EOF&&a)
    {
        n=n%48;
        for(i=3;i<=n;i++)
            fib[i]=(a*fib[i-1]+b*fib[i-2])%7;
        printf("%d\n",fib
);
    }
    return 0;
}