Linux数组，去掉重复的数值

 

#!/bin/sh 

 

array=("java" "linux" "c" "linux" "c++" "java") 

len=${#array[@]} 

for((i=0;i<$len;i++)) 

do 

  for((j=$len-1;j>i;j--)) 

  do 

    if [[ ${array[i]} = ${array[j]} ]];then 

      unset array[i] 

    fi 

  done 

done 

 

for arr in ${array[@]} 

do 

  echo $arr 

done 

[root@bogon shell]# ./array1.sh

c

linux

c++

java

以上代码，处理后的数组，如果用下标来访问数组元素，不一定准确。所以，后来将处理完后的数组元素值，重新赋给新的数组了。如下：

array1=("nbi_db" "information_schema" "mysql" "performance_schema" "test" "nbi_db")

length=${#array1[@]}

for  (( i=0; i<$length; i++ )); do

  for (( j=$(expr $length - 1); j>$i; j-- ));do

    if [[ "${array1[$i]}" = "${array1[$j]}" ]];then

      unset array1[$i]

    fi

  done

done

echo "array1 for ... in--------------"

index=0

for arr in ${array1[@]}

do

  echo "[$index] "$arr

  ((index++))

done

echo

echo "array1 for iterator------------"

for ((index=0;index<$length;index++))

do

  echo "[$index] "${array1[$index]}

done

echo

index=0

for arr in ${array1[@]};do

  array2[$index]=$arr

  ((index++))

done

echo

length=${#array2[@]}

for ((index=0;index<$length;index++))

do

  echo "array2[$index]="${array2[$index]}

done

运行结果：

array1 for ... in--------------

[0] information_schema

[1] mysql

[2] performance_schema

[3] test

[4] nbi_db

array1 for iterator------------

[0]

[1] information_schema

[2] mysql

[3] performance_schema

[4] test

[5] nbi_db

array2[0]=information_schema

array2[1]=mysql

array2[2]=performance_schema

array2[3]=test

array2[4]=nbi_db